ΔH°f (C2H5OH, l) = -277.4 kJ/mol
(to get 3H2 on left). [ 3H2 + 1.5O2 → 3H2O \quad ΔH = -857.4 , \textkJ ] 1972 ap chemistry free response answers
(since we want ethanol as product, not reactant). [ 2CO2 + 3H2O → C2H5OH + 3O2 \quad ΔH = +1367 , \textkJ ] ΔH°f (C2H5OH, l) = -277
[ [H^+] = \sqrt(0.100)(1.8 \times 10^-5) ] [ [H^+] = \sqrt1.8 \times 10^-6 ] 1972 ap chemistry free response answers
By: AP Curriculum Historians